4x^2-8x+12/x-3=4(x+1)

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Solution for 4x^2-8x+12/x-3=4(x+1) equation: 



4x^2-8x+12/x-3=4(x+1)

We move all terms to the left:

4x^2-8x+12/x-3-(4(x+1))=0



Domain of the equation: x!=0

x∈R



We multiply all the terms by the denominator


4x^2*x-8x*x-((4(x+1)))*x-3*x+12=0

We add all the numbers together, and all the variables

4x^2*x-3x-8x*x-((4(x+1)))*x+12=0

Wy multiply elements

4x^3-8x^2-3x-((4(x+1)))*x+12=0

We do not support expression: x^3

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